Quick answer: If an AP has n terms, first term a and last term l, its sum is Sₙ = n(a + l)/2. Each end-pair has the same sum; for odd n the middle term is half that pair sum.
Worked example
Find the sum 5 + 8 + 11 + … + 32.
- Use l = a + (n − 1)d: 32 = 5 + 3(n − 1).
- Thus n − 1 = 9 and n = 10.
- S₁₀ = 10(5 + 32)/2 = 185.
Check the result
Five end-pairs each total 37, so their combined sum is 5 × 37 = 185.
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Common mistake to avoid
The number of gaps is n − 1, not n. Do not apply this formula to a sequence without constant differences.
Try it yourself
1. Sum the first 20 positive integers. 2. Sum 4 + 9 + 14 + … + 49.
Answers and reasoning
1. 20(1 + 20)/2 = 210. 2. There are 10 terms; sum = 10(4 + 49)/2 = 265.
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