Quick answer: At a tangent's point of contact T, the radius OT is perpendicular to the tangent. The perpendicular from the centre is the shortest distance to that line; a closer point would force the line to cut the circle.
Worked example
A tangent PT touches a circle of radius 5 cm. If OP = 13 cm, find PT.
- OT = 5 cm and ∠OTP = 90°.
- OP is the hypotenuse of triangle OTP.
- PT² = OP² − OT² = 169 − 25 = 144.
- PT = 12 cm.
Check the result
The lengths 5, 12, 13 satisfy Pythagoras. P lies outside because OP > radius.
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Common mistake to avoid
The right angle is at T, not at the external point P. Use OP as the hypotenuse.
Try it yourself
1. Radius is 3 cm and OP = 5 cm; find PT. 2. Can an external tangent segment have OP smaller than the radius?
Answers and reasoning
1. PT = √(25 − 9) = 4 cm. 2. No: P would lie inside the circle, so no tangent from P exists.
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