Quick answer: Polynomial division must satisfy dividend = divisor × quotient + remainder. With a linear divisor, the remainder is constant. Include zero coefficients for missing powers when using synthetic division.
Worked example
Divide x³ − 2x² − 5x + 6 by x − 3.
- Using root 3 and coefficients 1, −2, −5, 6: bring down 1.
- Multiply by 3 and add to −2 to get 1.
- Multiply that by 3 and add to −5 to get −2.
- Multiply −2 by 3 and add to 6 to get 0. Quotient is x² + x − 2, remainder 0.
Check the result
(x − 3)(x² + x − 2) expands to x³ − 2x² − 5x + 6.
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Common mistake to avoid
For x + 3, use synthetic value −3. Missing coefficients, such as the x term in x² + 1, must be entered as zero.
Try it yourself
1. Divide x² − 1 by x − 1. 2. Divide x² + 1 by x − 1.
Answers and reasoning
1. Quotient x + 1, remainder 0. 2. Quotient x + 1, remainder 2, because (x − 1)(x + 1) + 2 = x² + 1.
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