Quick answer: The expansion of (a + b)ⁿ contains n + 1 formal terms. If n is even there is one middle term, Tₙ/₂₊₁. If n is odd there are two, T₍ₙ₊₁₎/₂ and T₍ₙ₊₃₎/₂.
Worked example
Find the middle term of (x + 1)⁶ and the middle terms of (x + 1)⁵.
- For n = 6, seven terms means the fourth is central.
- T₄ = 6C₃x³ = 20x³.
- For n = 5, six terms means the third and fourth are central.
- They are 5C₂x³ = 10x³ and 5C₃x² = 10x².
Check the result
The exponents in the first expansion are 6, 5, 4, 3, 2, 1, 0; x³ sits in the centre.
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Common mistake to avoid
Count terms using n + 1, not n. The binomial coefficient index is one less than the term number.
Try it yourself
1. Find the middle term of (a + b)⁴. 2. Find both middle terms of (x + 2)³.
Answers and reasoning
1. T₃ = 6a²b². 2. T₂ = 6x² and T₃ = 12x.
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